How do you solve $0.19 y + 0.02 (y + 2000) = 1300$ $0.19y + 0.02( y + 2000) = 1300$ ?

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Answer 1 · 2018-01-25T11:59:28

$y = 6000$ $y=6000$

$0.19 y + 0.02 (y + 2000) = 1300$ $0.19y + 0.02(y+2000) = 1300$

You can solve this by "expanding" the brackets. We rewrite the equation as follows.

$0.19 y + (0.02 \cdot y + 0.02 \cdot 2000) = 1300$ $0.19y + (0.02*y+0.02*2000) = 1300$
$0.19 y + 0.02 y + 40 = 1300$ $0.19y+0.02y+40=1300$

Next we isolate the variable.

$0.21 y + 40 - 40 = 1300 - 40$ $0.21y +40-40 = 1300-40$
$0.21 y = 1260$ $0.21y = 1260$

$\frac{0.21 y}{0.21} = \frac{1260}{0.21}$ $(0.21y)/0.21 = 1260/0.21$

$y = 6000$ $y=6000$

How do you solve 0.19y + 0.02( y + 2000) = 13000.19y+0.02(y+2000)=13000.19y + 0.02( y + 2000) = 1300?