Question

Question #31d8a

Answer 1

`y=a^x`
Take `log` on both sides
`logy=log(a)^x`
`logy=xloga`
Derivative w.r.t. `x`
`1/y(dy/dx)=loga`
`dy/dx=yloga`
put the value of `y`
`dy/dx=(a)^xloga`