Question #c2658

1 Answer
Nityananda
Jan 27, 2018

#x = (1+sqrt5), (1-sqrt5)#

Explanation:

Given, #x^2-2x=4#
#rArr x^2-2x-4=0#
#rArr x^2-2x+1-5=0#
#rArr (x-1)^2-(sqrt5)^2=0#
#rArr [(x-1)+sqrt5][(x-1)-sqrt5]=0#
#rArr [(x-1)+sqrt5]=0,[(x-1)-sqrt5]=0#
#rArr (x-1+sqrt5)=0, (x-1-sqrt5)=0#
#rArr x = (1-sqrt5), (1+sqrt5)#

Related questions
Impact of this question
782 views around the world
You can reuse this answer
Creative Commons License