Question #03095

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Question #03095

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Answer 1 · 2018-01-29T02:57:28

$44 %$ $44%$

Explanation:

Length of side of square = $30$ $30$ cm

Increase in length = $20 %$ $20%$

So, new length = $30 \times \frac{120}{100}$ $30xx 120/100$ = $36$ $36$ cm

Now, area of original square = $30 \times 30$ $30xx30$ = $900 c m^{2}$ $900 cm^2$

Area of square with $20 %$ $20%$ increased length = $36 \times 36$ $36xx36$ = $1296 c m^{2}$ $1296cm^2$

Change in area = $1296 - 900$ $1296-900$ = $396 c m^{2}$ $396 cm^2$ (we divide by $900$ $900$ and nor by $1296$ $1296$ because the increase in area or change in area is as compared to the original area)

Percent increase in area = $\frac{396}{900} \times 100$ $396/900 xx100$ = $44 %$ $44%$

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Question #03095

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