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Question #b01d3

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Jan 31, 2018

If balloon gains a charge of $- 8 μ C$ $-8 muC$ then denim has gained a charge of $+ 8 μ C$ $+8muC$ .

The force of attraction between them when they are separated by a distance of 5 cm is given as:

$F = \frac{1}{4 \cdot π \cdot ε_{0}} \cdot \frac{q_{1} \cdot q_{2}}{r^{2}}$ $F= 1/(4*pi*epsilon_0)*(q_1*q_2)/r^2$

where,
$ε_{0} = 8.85 \cdot 10^{- 12} \frac{F}{m}$ $epsilon_0 = 8.85 *10^-12 F/m$
(assuming there is air between the balloon and the denim)

$q_{1} = - 8 μ C$ $q_1= -8 muC$
$q_{2} = + 8 μ C$ $q_2= +8 muC$
$r = 5 \cdot 10^{- 2} m$ $r = 5*10^-2 m$

Substituting all the values in the equation we obtain force as,
-230.19 N. Negative value of F indicates the force is attractive in nature.

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