How do you evaluate $x^{- 2} {[x^{6} {[x {(x^{- 3})}^{\frac{1}{3}}]}^{\frac{1}{9}}}}^{\frac{2}{3}}$ $x^ { - 2} [ x ^ { 6} [ x ( x ^ { - 3} ) ^ { \frac { 1} { 3} } ] ^ { \frac { 1} { 9} } \} ^ { \frac { 2} { 3} }$ ?

Question

How do you evaluate $x^{- 2} {[x^{6} {[x {(x^{- 3})}^{\frac{1}{3}}]}^{\frac{1}{9}}}}^{\frac{2}{3}}$ $x^ { - 2} [ x ^ { 6} [ x ( x ^ { - 3} ) ^ { \frac { 1} { 3} } ] ^ { \frac { 1} { 9} } \} ^ { \frac { 2} { 3} }$ ?

1 Answer

Impact of this question

1208 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-01T12:02:58

$x^{2}$ $x^2$

Explanation:

Given, $x^{- 2} {[x^{6} {x {(x^{- 3})}^{\frac{1}{3}}}^{\frac{1}{9}}]}^{\frac{2}{3}}$ $x^-2[x^6{x(x^-3)^(1/3)}^(1/9)]^(2/3)$
$\Rightarrow x^{- 2} {[x^{6} {x^{1} {(x^{- 3})}^{\frac{1}{3}}}^{\frac{1}{9}}]}^{\frac{2}{3}}$ $rArr x^-2[x^6{x^1(x^-3)^(1/3)}^(1/9)]^(2/3)$
$\Rightarrow x^{- 2} {[x^{6} {x^{1} x^{- 1}}^{\frac{1}{9}}]}^{\frac{2}{3}}$ $rArr x^-2[x^6{x^1x^-1}^(1/9)]^(2/3)$
$\Rightarrow x^{- 2} {[x^{6} {x^{1 - 1}}^{\frac{1}{9}}]}^{\frac{2}{3}}$ $rArr x^-2[x^6{x^(1-1)}^(1/9)]^(2/3)$
$\Rightarrow x^{- 2} {[x^{6} {x^{0}}^{\frac{1}{9}}]}^{\frac{2}{3}}$ $rArr x^-2[x^6{x^0}^(1/9)]^(2/3)$
$\Rightarrow x^{- 2} {[x^{6} {1}^{\frac{1}{9}}]}^{\frac{2}{3}}$ $rArr x^-2[x^6{1}^(1/9)]^(2/3)$
$\Rightarrow x^{- 2} {[x^{6} \cdot 1]}^{\frac{2}{3}}$ $rArr x^-2[x^6 *1]^(2/3)$
$\Rightarrow x^{- 2} x^{6 \cdot \frac{2}{3}}$ $rArr x^-2 x^(6*2/3)$
$\Rightarrow x^{- 2} x^{4}$ $rArr x^-2 x^4$
$\Rightarrow x^{- 2 + 4}$ $rArr x^(-2+4)$
$\Rightarrow x^{2}$ $rArr x^2$

Science

Math

Humanities

... and beyond

How do you evaluate $x^{- 2} {[x^{6} {[x {(x^{- 3})}^{\frac{1}{3}}]}^{\frac{1}{9}}}}^{\frac{2}{3}}$ $x^ { - 2} [ x ^ { 6} [ x ( x ^ { - 3} ) ^ { \frac { 1} { 3} } ] ^ { \frac { 1} { 9} } \} ^ { \frac { 2} { 3} }$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you evaluate x−2[x6[x(x−3)13]19}23x^ { - 2} [ x ^ { 6} [ x ( x ^ { - 3} ) ^ { \frac { 1} { 3} } ] ^ { \frac { 1} { 9} } \} ^ { \frac { 2} { 3} }?

1 Answer

Explanation:

Related questions

Impact of this question

How do you evaluate $x^{- 2} {[x^{6} {[x {(x^{- 3})}^{\frac{1}{3}}]}^{\frac{1}{9}}}}^{\frac{2}{3}}$ $x^ { - 2} [ x ^ { 6} [ x ( x ^ { - 3} ) ^ { \frac { 1} { 3} } ] ^ { \frac { 1} { 9} } \} ^ { \frac { 2} { 3} }$ ?