Question #82413

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Answer 1 · 2018-02-05T19:17:17

Given $f (x)$ $f(x)$ , the average rate of change from $x_{1} = a$ $x_1 = a$ to $x_{2} = b$ $x_2 = b$ is:

$Average rate of change = \frac{f (b) - f (a)}{b - a}$ $"Average rate of change"= (f(b)-f(a))/(b-a)$

In this problem, we are given that:

$f(x)=x^2+5x−8$ , $x_1 = 2$ , and $x_2 = 6$

$"Average rate of change"= (f(6)-f(2))/(6-2)$

$"Average rate of change"= (6^2+5(6)−8-(2^2+5(2)−8))/4$

$"Average rate of change"= 13$

Answer 2 · 2018-02-05T19:21:40

$(f(6)-f(2))/(6-2)=13$

$f(6)=6^2+6.5-8=58$

$f(2)=2^2+2.5-8=6$

$6-2=4$