Question #82413

2 Answers
Feb 5, 2018

Given f(x)f(x), the average rate of change from x_1 = ax1=a to x_2 = bx2=b is:

"Average rate of change"= (f(b)-f(a))/(b-a)Average rate of change=f(b)f(a)ba

Explanation:

In this problem, we are given that:

f(x)=x^2+5x−8​, x_1 = 2, and x_2 = 6

"Average rate of change"= (f(6)-f(2))/(6-2)

"Average rate of change"= (6^2+5(6)−8-(2^2+5(2)−8))/4

"Average rate of change"= 13

Feb 5, 2018

(f(6)-f(2))/(6-2)=13

Explanation:

f(6)=6^2+6.5-8=58

f(2)=2^2+2.5-8=6

6-2=4