Question #0b882

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Question #0b882

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Answer 1 · 2018-02-10T10:08:48

$1250$ $1250$ calories

Explanation:

To convert the temperature of mass $m$ $m$ from $θ_{1}$ $theta_1$ to $θ_{2}$ $theta_2$ ,having a specific heat of $s$ $s$ ,heat energy( $H$ $H$ ) required is given as, $H = m s (θ_{2} - θ_{1})$ $H= ms (theta_2 - theta_1)$

Here, $m = 50 g m, (θ_{2} - θ_{1}) = (50 - 25) = 25, s = 1$ $m=50 gm , (theta_2 - theta_1) =(50-25)=25,s=1$ CGS unit for water)

So, $H = 50 \cdot 1 \cdot 25 = 1250$ $H = 50*1*25 = 1250$ calories

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