Question #a21ee

1 Answer
Øko
Feb 13, 2018

#I=2tan(x/2)+C#

Explanation:

We want to integrate

#I=intsec^2(x/2)dx#

Make a substitution #u=x/2=>(du)/dx=1/2#
(Hence the 2 in front of tan)

#I=intsec^2(u)1/(1/2)du#

#=2intsec^2(u)du#

#=2tan(u)+C#

Substitute #u=x/2#

#=2tan(x/2)+C#

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