A room kept at STP is filled with ozone, $O_3$ contains a total of $5.41 xx 10^58$ atoms of oxygen. What is the volume (in liters) of the room?

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Answer 1 · 2018-02-13T13:52:37

$201.6L$

Well, at $STP$ (since 1982), one mole of an ideal gas would have a volume of $22.4L$ .

So, we have:

$"moles"_(O_3)=(5.41*10^58)/(6.02*10^23)~~9mol$

So, the total volume will be

$9*22.4=201.6L$

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A room kept at STP is filled with ozone, O_3O_3 contains a total of 5.41 xx 10^585.41 xx 10^58 atoms of oxygen. What is the volume (in liters) of the room?