Question

Question #83103

Answer 1

`y=(5/2)x+0`

Explanation:

First step is to find the y intercept, where `x=0`
`x=(2/5)y`
`(0)=(2/5)y`
`(0)/(2/5)=((2/5)y)/(2/5)`
`y=0`

This means that when `x=0`, then `y=0`, which can be described as `(0,0)`, and means that this line passes through the origin.

Now we can convert to the slope-intercept form, `y=mx+b`
`x=(2/5)y`
`x/(2/5)=((2/5)y)/(2/5)`
`x(5/2)=y`
`y=(5/2)x+0`

Breaking down this equation will help you graph it. b is the y intercept, or where the line crosses the y axis. Since the origin is a defined point, that is the y intercept

m represents the slope, which shows the direction and angle of the line. This is also described as 'rise over run.' Since the slope is `5/2`, then from the y intercept (the origin), count up 5 and to the right 2. this is represented as `(2,5)`. From here, you can continue plotting points by adding 5 to each y value as you add 2 to each x value.

graph{y=5/2(x) [-10, 10, -5, 5]}