Question #281de

2 Answers

Alkenyl radicals with formula C4H7 are seven

Explanation:

Consider first the alkenes with formula C4H8:
They are
1) H2C=CH-CH2-CH3
2) H3C-CH=CH-CH3
3) H2C=C(CH3)2

From 1 there are three radicals possibles:

1a) H2C=CH-CH2-CH2
1b) H2C=CH-CH
-CH3
1c) H2C=C*-CH2-CH3

From 2 the possibilities are:

2a) H3C-CH=CH-CH2
2b) H3C-CH=C
-CH3

From 3:

3a) #"H"_3"C-C=CH"_2#
#"color(white)(mmmmll)|#
#color(white)(mmmml)"CH"_2"*"#

3b) #"H"_3"C-C=CH*"#
#color(white)(mmmmll)|#
#color(white)(mmmml)"CH"_3#

In total seven radicals

Feb 16, 2018

I count ten alkenyl radicals with the formula #"C"_4"H"_7#.

Explanation:

From but-1-ene

1. #"H"stackrelcolor(blue)(bb·)("C")"=CHCH"_2"CH"_3#

2. #"H"_2"C="stackrelcolor(blue)(bb·)("C")"CH"_2"CH"_3#

3. #"H"_2"C=CH"stackrelcolor(blue)(bb·)("C")"HCH"_3#

4. #"H"_2"C=CHCH"_2stackrelcolor(blue)(bb·)("C")"H"_2#

From but-2-ene

5. and 6. #stackrelcolor(blue)(bb·)("C")"H"_2"CH=CHCH"_3# (#E"-"# and #Z"-"#isomers)

7. and 8. #"CH"_3stackrelcolor(blue)(bb·)("C")"=CHCH"_3# (#E"-"# and #Z"-"#isomers)

From 2-methylpropene

9. #stackrelcolor(blue)(bb·)("C")"H"_2"C"("CH"_3)"=CH"_2#

10. #("CH"_3)_2"C="stackrelcolor(blue)(bb·)("C")"H"#