Two strings are tuned to the same pitch ( $184$ Hz). Later you increase the tension in one string. Now, when both strings are played, there are 2 beats every second. What is the new frequency of the string that was tuned?

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Two strings are tuned to the same pitch ( $184$ Hz). Later you increase the tension in one string. Now, when both strings are played, there are 2 beats every second. What is the new frequency of the string that was tuned?

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Answer 1 · 2018-02-17T11:07:41

186 Hz

Explanation:

We know,velocity of a wave= $"frequency"xx lamda$
also, velocity = $sqrt(Tension//mu)$
now,if i increase the tension in one of them,velocity increases and consequently the frequency becomes higher,
thus,the value of the new frequency will be greater than 184Hz.
we know, $n_1~n_2="beat" " frequency"$
plugging in the values,.
$n_1$ =184+2 or 186Hz

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Two strings are tuned to the same pitch ( $184$ Hz). Later you increase the tension in one string. Now, when both strings are played, there are 2 beats every second. What is the new frequency of the string that was tuned?

1 Answer

Explanation:

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Science

Math

Humanities

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Two strings are tuned to the same pitch (184184 Hz). Later you increase the tension in one string. Now, when both strings are played, there are 2 beats every second. What is the new frequency of the string that was tuned?

1 Answer

Explanation:

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Impact of this question

Two strings are tuned to the same pitch ( $184$ Hz). Later you increase the tension in one string. Now, when both strings are played, there are 2 beats every second. What is the new frequency of the string that was tuned?