Question #6a568

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Answer 1 · 2018-02-19T16:12:24

I guess you want me to simplify

$sinx/(sinx+1)=$

$sinx/(sinx+1)*(sinx-1)/(sinx-1)=$

$(sin^2x-sinx)/(sin^2x-1)=$

$(sin^2x-sinx)/(sin^2x-(sin^2x+cos^2x))=$

$(sin^2x-sinx)/(-cos^2x)=$

$(sin^2x(1-cscx))/(-cos^2x)=$

$-tan^2x(1-cscx)=$

$-tan^2x+(sinx/cos^2x)=$

$-tan^2x+tanx*secx=$

$-tanx(tanx-secx)$