Question #ce2b1

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Answer 1 · 2018-02-20T06:38:34

See the explanation

A term in a GP is represented by $a r^{n - 1}$ $ar^(n-1)$ .

Here , a is the first term.

$\to$ $->$ r is the common ratio.

$\to$ $->$ n is the number of term.

For finding the first four terms calculate $a_{2}, a_{3}, a_{4}$ $a_2 , a_3 , a_4$

$\to a_{1} = 2$ $-> a_1 = 2$

$\to a_{2} = 2 \times 4^{2 - 1}$ $-> a_2 = 2 times 4^(2-1)$

$= 2 \times 4$ $" " = 2 times 4$

$= 8$ $" " = 8$

Similarly , $a_{3} = 32 and a_{4} = 128$ $a_3 = 32 and a_4 = 128$

So , the first four terms of the GP are

$2, 8, 32, 128$ $2 , 8 , 32 , 128$