A line with a slope of 1/313 passes through the point (3,6)(3,6). What point lies on this line?

1 Answer
Shreya
Feb 21, 2018

see below

Explanation:

the general equation of a straight line is y=mx +cy=mx+c where "mm represents the slope.
In this case,y=x//3 +cy=x/3+c
Plugging in the coordinates of the point(3,6)(3,6),we get cc as
6-1 or 5.
Thus the required equation of the straight line is y=x//3 +5y=x/3+5
Now for different values of (x,y)(x,y),we shall get the coordinates of different points which lie on this line.

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