C(-10, -16); r = 2 what is the equation?

1 Answer
Feb 22, 2018

\text{Standard form:}Standard form:

(x +10)^2 + (y +16)^2 = 4(x+10)2+(y+16)2=4

\text{General form:}General form:

x^2+y^2+20x+32y+356=0x2+y2+20x+32y+356=0

Explanation:

The standard form of the equation of circle is given as;

(x – h)^2 + (y – k)^2 = r^2

where, (h\ , \,k) represents the point at which the center of the circle lies and r represents the radius.


For the center at (h\ , \ k)=(-10\ ,\ -16) and radius r=2, we have the equation in standard form of circle as:

(x – (-10))^2 + (y –(-16))^2 = (2)^2

Simplify to get:

(x +10)^2 + (y +16)^2 = 4

Expand, the expression if you want to change it into general form.

x^2+20x+y^2+32y+356=0