C(-10, -16); r = 2 what is the equation?

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Answer 1 · 2018-02-22T14:48:12

$Standard form:$ $\text{Standard form:}$

${(x + 10)}^{2} + {(y + 16)}^{2} = 4$ $(x +10)^2 + (y +16)^2 = 4$

$General form:$ $\text{General form:}$

$x^{2} + y^{2} + 20 x + 32 y + 356 = 0$ $x^2+y^2+20x+32y+356=0$

The standard form of the equation of circle is given as;

$(x – h)^2 + (y – k)^2 = r^2$

where, $(h\ , \,k)$ represents the point at which the center of the circle lies and $r$ represents the radius.

For the center at $(h\ , \ k)=(-10\ ,\ -16)$ and radius $r=2$ , we have the equation in standard form of circle as:

$(x – (-10))^2 + (y –(-16))^2 = (2)^2$

Simplify to get:

$(x +10)^2 + (y +16)^2 = 4$

Expand, the expression if you want to change it into general form.

$x^2+20x+y^2+32y+356=0$