How do you solve (2b + 5) ( b - 3) = b ^ { 2} - 3?

1 Answer
Shreya
Feb 22, 2018

b=4 or -3

Explanation:

(2b-5)(b-3)=b^2-3
Simplifying,
2b^2-b^2-6b+5b-15+3=0
or,b^2-b-12=0
Carrying out middle term factorisation,we have,
b^2-4b+3b-12=0
(b-4)(b+3)=0
Thus,b-4=0 or b+3=0
We have, b=4 or -3

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