Question

Question #6cbbb

Answer 1

`CuO(s)+2HCl(aq)->CuCl_2(aq)+H_2O(l)`

Explanation:

This is a neutralization reaction. In a neutralization reaction, the chemical equation is as follows:

`"acid + base" \ -> \ "salt + water"`

Here, we got `CuO` as a base, since it can react with water to form `Cu(OH)_2`, which is a basic solution. The acid here is `HCl`.

So, our reaction will be

`CuO(s)+HCl(aq)->CuCl_2(aq)+H_2O(l)`

To balance it, I see `2` chlorines on the right side, while only one on the left side, so I multiply `HCl` by `2`. This gives us:

`CuO(s)+2HCl(aq)->CuCl_2(aq)+H_2O(l)`

This is also a reaction that has been covered here:

https://socratic.org/questions/cuo-s-hcl-aq-equation-and-net-ionic-equation

Answer 2

`"CuO" + "2HCl" rarr "CuCl"_2+"H"_2"O"`

Explanation:

It is a double displacement reaction, where positive charged elements change their negative pairs.

What I mean is:
`"Cu"^(+2) "O"^(-2)+ "H"^(+1)"Cl"^(-1) rarr "CuCl"_2 + "OH"`

But we need to balance it so:
`"CuO" + 2"HCl" rarr "CuCl"_2 + "H"_2"O"`

This happens because the products have an extra Chlorine (`"Cl"`) so we multiply `"HCl"` by `2` and, therefore, add a Hydrogen (`"H"`) to the products, as well.