Question #17455

1 Answer
dani83
Feb 28, 2018

lim_{x->0} (x+sin3x)/(2x+sin5x) = lim_{x->0} (1+3cos3x)/(2+5cos5x) = 4/7

Explanation:

Using l'Hopital's rule:
lim_{x->0} (x+sin3x)/(2x+sin5x) = lim_{x->0} (1+3cos3x)/(2+5cos5x) = 4/7

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