Calculate the percentage yield of the reaction?

Question

Magnesium reacts with oxygen as shown in the equation below:

$2 M g + O_{2} \to 2 M g O$ $2Mg+O_2 ->2MgO$

Calculate the percentage yield of the reaction, given that burning 2.32g of magnesium produced 2.39g of magnesium oxide. (4 marks)

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Answer 1 · 2018-02-28T19:22:26

61.9%

1 mole of Mg give 1 mole of MgO
or 24 g of Mg gives 40 g of Mgo

Thus, 2.32 g of Mg will give $\frac{40}{24} \cdot 2.32$ $40/24*2.32$ = 3.86 g
3.86 is given by sample with 100% yield i.e. expected

But actually we obtained( 2.39 g

Percent yield= (Obtained)/ (Expected ) * 100

= $\frac{2.39}{3.86} \cdot 100 = 61.9 %$ $(2.39)/(3.86)*100=61.9%$