Please help? Solve the equation fro exact solutions over the interval (0degrees, 360 degrees)

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Please help? Solve the equation fro exact solutions over the interval (0degrees, 360 degrees)

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Answer 1 · 2018-03-02T18:43:06

1.

$θ = 240^{\circ}, 300^{\circ}$ $theta=240^@,300^@$

2.

$θ = 120^{\circ}, 240^{\circ}$ $theta=120^@,240^@$

Explanation:

1.

$3 sin (θ) = sin (θ) - \sqrt{3}$ $3sin(theta)=sin(theta)-sqrt(3)$

$\Rightarrow 2 sin (θ) = - \sqrt{3}$ $=>2sin(theta)=-sqrt(3)$

$\Rightarrow sin (θ) = - \frac{\sqrt{3}}{2}$ $=>sin(theta)=-sqrt(3)/2$

$\Rightarrow θ = 240^{\circ}, 300^{\circ}$ $=>theta=240^@,300^@$

2.

$5 cos (θ) = 3 cos (θ) - 1$ $5cos(theta)=3cos(theta)-1$

$\Rightarrow 2 cos (θ) = - 1$ $=>2cos(theta)=-1$

$\Rightarrow cos (θ) = - \frac{1}{2}$ $=>cos(theta)=-1/2$

$\Rightarrow θ = 120^{\circ}, 240^{\circ}$ $=>theta=120^@,240^@$

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Please help? Solve the equation fro exact solutions over the interval (0degrees, 360 degrees)

1 Answer

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