How do you expand #log (6/11)^5#?
1 Answer
Mar 3, 2018
Explanation:
#log(6/11)^5 = 5 log(6/11)# because#log a^b = b log a# #=5(log 6 -log 11)# because#log(a/b)=log a - log b# #=5log 6 -5log 11# because#a(b-c)=ab-ac#
