Question

How do you evaluate `(4- 2) \cdot 6\div 3+ ( 5- 2) ^ { 2}`?

Answer 1

See below.

Explanation:

We must use order of operations to solve this problem.

P: parentheses
E: exponents
M: multiplication
D: division
A: addition
S: subtraction

Now, since the problem is `(4-2)*6-:3+(5-2)^2`, you must look and say to yourself, "Is there any parentheses?"

`color(blue)((4-2))*6-:3+color(blue)((5-2))^2`

Now, solve those parentheses, and you get

`2*6-:3+3^2`

So now, you must look at the equation and say to yourself, "Any exponents?" Since `3^2` is an exponent, you must solve the problem `3*3`. Now, you are left with

`2*6-:3+9`

Time for multiplication! Look for any multiplication, and solve it. You are now left with

`12-:3+9`

Since there is division, you must now solve that, and you will end up with

`4+9`

which can be solved using addition, to get your final answer of `13`.