A rectangle has a perimeter of 24 inches. What are its dimensions if its length is 3 inches greater than its width?

Question

A rectangle has a perimeter of 24 inches. What are its dimensions if its length is 3 inches greater than its width?

1 Answer

Impact of this question

10485 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-03T13:04:59

The shorter side is 4.5 inches, the longer is 7.5 inches.

Explanation:

The perimeter formula for a rectangle is $P = 2 l + 2 w$ $P = 2l + 2w$
(Perimeter = 2 length + 2width)
Let $x$ $x$ = width, then the length is 3 inches greater than the width, so
Let $x + 3$ $x + 3$ = length.

Substitute into the formula to get:

$24 = 2 (x + 3) + 2 (x)$ $24 = 2(x+3) + 2(x)$

Simplify (distribute then collect like terms) to:

$24 = 4 x + 6$ $24 = 4x+6$

Solve this for $x$ $x$ :

$\ 24 = 4x+6$
$-6 \ \ \ \ \ \ \ \ \ \ -6$
$\ 18 =4x$
$4.5 = x$
$x + 3 = 7.5$

Science

Math

Humanities

... and beyond

A rectangle has a perimeter of 24 inches. What are its dimensions if its length is 3 inches greater than its width?

1 Answer

Explanation:

Related questions

Impact of this question