What is the corredt answer?

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What is the corredt answer?

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Answer 1 · 2018-03-03T14:37:04

$\frac{3}{x - 1} + \frac{4}{1 - 2 x} = \frac{2 x + 1}{(x - 1) (2 x - 1)}$ $3/(x-1)+4/(1-2x)=(2x+1)/((x-1)(2x-1))$

Explanation:

We begin by bringing the two terms under a common denominator:
$\frac{3}{x - 1} + \frac{4}{1 - 2 x} = \frac{3 (1 - 2 x)}{(x - 1) (1 - 2 x)} + \frac{4 (x - 1)}{(x - 1) (1 - 2 x)}$ $3/(x-1)+4/(1-2x)=(3(1-2x))/((x-1)(1-2x))+(4(x-1))/((x-1)(1-2x))$

Now we can just add the numerators:
$\frac{3 (1 - 2 x) + 4 (x - 1)}{(x - 1) (1 - 2 x)} = \frac{3 - 6 x + 4 x - 4}{(x - 1) (1 - 2 x)} =$ $(3(1-2x)+4(x-1))/((x-1)(1-2x))=(3-6x+4x-4)/((x-1)(1-2x))=$

$= \frac{- 1 - 2 x}{(x - 1) (1 - 2 x)}$ $=(-1-2x)/((x-1)(1-2x))$

Bring out a minus on both the top and bottom, making them cancel:
$\frac{- (2 x + 1)}{(x - 1) (- (- 1 + 2 x))} = \frac{- (2 x + 1)}{- (x - 1) (2 x - 1)} =$ $(-(2x+1))/((x-1)(-(-1+2x)))=(-(2x+1))/(-(x-1)(2x-1))=$

$= \frac{2 x + 1}{(x - 1) (2 x - 1)}$ $=(2x+1)/((x-1)(2x-1))$ which is option $C$ $C$

Answer 2 · 2018-03-03T14:38:52

$C$ $C$

Explanation:

$\frac{3}{x - 1} + \frac{4}{1 - 2 x}$ $3/(x-1) + 4/(1-2x)$

$= \frac{3 - 6 x + 4 x - 4}{(x - 1) (1 - 2 x)}$ $=(3-6x+4x-4)/((x-1)(1-2x)$

$= - \frac{2 x + 1}{(x - 1) (1 - 2 x)}$ $= -(2x+1)/((x-1) (1-2x))$

$= \frac{2 x + 1}{(x - 1) (2 x - 1)}$ $=(2x+1)/((x-1)(2x-1)$ (multiplied $(1 - 2 x)$ $(1-2x)$ with the negative sign)

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