How do you solve the system of equations 2a-4b=6 and a+3b=-7?

1 Answer
Mar 5, 2018

a=-1, b=-2

Explanation:

Multiplying the second equation by 2, we have 2a+6b=-14. Subtracting this equation into the first equation that was given in the problem => 10b=-20 => b=-2.
We now know b=-2, solving for a should be easy. Plug b=-2 into any one of the equation, and then solve for a => a+3(-2)=-7 => a-6=-7 => a=-1