I want to know how to integrate Sin(2x)*Sin(5x)dx?
1 Answer
Mar 5, 2018
#I=1/42(7sin(3x)-3sin(7x))+C#
Explanation:
We want to solve
#I=intsin(2x)sin(5x)dx#
Use the product identity
#sin(a)sin(b)=1/2(cos(a-b)-cos(a+b))#
With
#I=1/2int(cos(3x)-cos(7x))dx#
Which is much more comfortable to integrate
#I=1/2(1/3sin(3x)-1/7sin(7x))+C#
Or
#I=1/42(7sin(3x)-3sin(7x))+C#