Write a balanced equation to show the reation of sulfurus acid with lithium hydroxide to form lithium sulfite and water ??

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Write a balanced equation to show the reation of sulfurus acid with lithium hydroxide to form lithium sulfite and water ??

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Answer 1 · 2018-03-05T15:50:23

$H_{2} {SO}_{3} (a q) + 2 LiOH (s) \to {Li}_{2} {SO}_{3} (a q) + 2 H_{2} O (l)$ $"H"_2"SO"_3(aq)+2"LiOH"(s)rarr"Li"_2"SO"_3(aq)+2"H"_2"O"(l)$

Explanation:

Sulfurous acid is given by $H_{2} {SO}_{3}$ $"H"_2"SO"_3$ . Lithium hydroxide by $LiOH$ $"LiOH"$ , lithium sulfite by ${Li}_{2} {SO}_{3}$ $"Li"_2"SO"_3$ and water by $H_{2} O$ $"H"_2"O"$ .

We now have:

$H_{2} {SO}_{3} + LiOH \to {Li}_{2} {SO}_{3} + H_{2} O$ $"H"_2"SO"_3+"LiOH"rarr"Li"_2"SO"_3+"H"_2"O"$
Balancing this, we get:

$H_{2} {SO}_{3} (a q) + 2 LiOH (s) \to {Li}_{2} {SO}_{3} (a q) + 2 H_{2} O (l)$ $"H"_2"SO"_3(aq)+2"LiOH"(s)rarr"Li"_2"SO"_3(aq)+2"H"_2"O"(l)$

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Write a balanced equation to show the reation of sulfurus acid with lithium hydroxide to form lithium sulfite and water ??

1 Answer

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