Question

Write a balanced equation to show the reation of sulfurus acid with lithium hydroxide to form lithium sulfite and water ??

Answer 1

`"H"_2"SO"_3(aq)+2"LiOH"(s)rarr"Li"_2"SO"_3(aq)+2"H"_2"O"(l)`

Explanation:

Sulfurous acid is given by `"H"_2"SO"_3`. Lithium hydroxide by `"LiOH"`, lithium sulfite by `"Li"_2"SO"_3` and water by `"H"_2"O"`.

We now have:

`"H"_2"SO"_3+"LiOH"rarr"Li"_2"SO"_3+"H"_2"O"`
Balancing this, we get:

`"H"_2"SO"_3(aq)+2"LiOH"(s)rarr"Li"_2"SO"_3(aq)+2"H"_2"O"(l)`