How do you evaluate ${(- 6)}^{2} + 5 (- 6) - 5$ $(- 6) ^ { 2} + 5( - 6) - 5$ ?

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How do you evaluate ${(- 6)}^{2} + 5 (- 6) - 5$ $(- 6) ^ { 2} + 5( - 6) - 5$ ?

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Answer 1 · 2018-03-06T05:56:05

$1$ $1$

Explanation:

We've got three terms to simplify. We first simply them one by one and do the required operation.

${(- 6)}^{2} + 5 (- 6) - 5$ $(-6)^2+5(-6)-5$
$= (- 6) \cdot (- 6) + 5 (- 6) - 5$ $=(-6)*(-6)+5(-6)-5$
$= 36 - 30 - 5$ $=36-30-5$
$= 36 - 35$ $=36-35$
$= 1$ $=1$

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How do you evaluate ${(- 6)}^{2} + 5 (- 6) - 5$ $(- 6) ^ { 2} + 5( - 6) - 5$ ?

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