How do you solve the following system of equations?: $x - 2 y = 13, x - y = 10$ $x-2y=13 , x - y= 10$ ?

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How do you solve the following system of equations?: $x - 2 y = 13, x - y = 10$ $x-2y=13 , x - y= 10$ ?

1 Answer

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Answer 1 · 2018-03-07T09:31:40

lettuce solve for $x$ $x$ as it is same in both equations

$1^{s t} e q u a t i o n$ $1^(st)equation$
$x - 2 y = 13$ $x-2y=13$
Transfer $2 y$ $2y$
$x = 13 + 2 y$ $x=13+2y$

$2^{n d} e q u a t i o n$ $2^(nd)equation$
$x - y = 10$ $x-y=10$
Put value of $x$ $x$
$13 + 2 y - y = 10$ $13+2y-y=10$
Solve
$13 + y = 10$ $13+y=10$
Transfer $13$ $13$
$y = 10 - 13$ $y=10-13$
$y = - 3$ $color(red)(y=-3$
$x = 13 + 2 y$ $x=13+2y$
$x = 13 + 2 \times - 3$ $x=13+2xx-3$
$x = 13 - 6$ $x=13-6$
$x = 7$ $color(red)(x=7$

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How do you solve the following system of equations?: $x - 2 y = 13, x - y = 10$ $x-2y=13 , x - y= 10$ ?

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How do you solve the following system of equations?: x−2y=13,x−y=10x-2y=13 , x - y= 10?

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How do you solve the following system of equations?: $x - 2 y = 13, x - y = 10$ $x-2y=13 , x - y= 10$ ?