How do you simplify $8 - {[14 \div 7]}^{3} \cdot 2$ $8- [ 14\div 7] ^ { 3} \cdot 2$ ?

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Answer 1 · 2018-03-09T00:08:28

$- 8$ $-8$

First, work in the brackets/parenthesis

$[14 \div 7] = 2$ $[14 div7] = 2$

So

$8 - 2^{3} \cdot 2$ $8 - 2^3 * 2$

Then do the exponent

$8 - 8 \cdot 2$ $8 - 8 * 2$

Multiply first

$8 - 16$ $8 - 16$

then subtract

$- 8$ $-8$

How do you simplify 8−[14÷7]3⋅28- [ 14\div 7] ^ { 3} \cdot 2?