How do you solve $5 w^{2} + 28 w = - 32$ $5w ^ { 2} + 28w = - 32$ ?

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How do you solve $5 w^{2} + 28 w = - 32$ $5w ^ { 2} + 28w = - 32$ ?

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Answer 1 · 2018-03-10T05:17:27

w = - 4 or - 8/5

Explanation:

Given, $5 w^{2} + 28 w = - 32$ $5w^2+28w = -32$
$\Rightarrow 5 w^{2} + 28 w + 32 = 0$ $rArr 5w^2+28w+32=0$
$\Rightarrow 5 w^{2} + (20 + 8) w + 32 = 0$ $rArr 5w^2+(20+8)w+32=0$
$\Rightarrow 5 w^{2} + 20 w + 8 w + 32 = 0$ $rArr 5w^2+20w+8w+32=0$
$\Rightarrow 5 w (w + 4) + 8 (w + 4) = 0$ $rArr 5w(w+4)+8(w+4)=0$
$\Rightarrow (w + 4) (5 w + 8) = 0$ $rArr (w+4)(5w+8)=0$
$\Rightarrow (w + 4) = 0, (5 w + 8) = 0$ $rArr (w+4)=0,(5w+8)=0$
$\Rightarrow w = - 4, w = - \frac{8}{5}$ $rArr w = -4, w =-8/5$
$\Rightarrow w = - 4 or - \frac{8}{5}$ $rArr w = -4 or -8/5$

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How do you solve $5 w^{2} + 28 w = - 32$ $5w ^ { 2} + 28w = - 32$ ?

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