How do you find the slope and intercept of $y=(5-x)/10$ ?

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Answer 1 · 2018-03-10T11:38:06

See a solution process below

Rewrite the equation in slope intercept form. The slope-intercept form of a linear equation is: $y = color(red)(m)x + color(blue)(b)$

Where $color(red)(m)$ is the slope and $color(blue)(b)$ is the y-intercept value.

$y = (5 - x)/10$

$y = 5/10 - x/10$

$y = 1/2 - 1/10x$

$y = color(red)(-1/10)x + color(blue)(1/2)$

Therefore:

Answer 2 · 2018-03-10T11:39:06

Slope
$m=-0.1$
Intercept
$c=0.5$

Given:
$y=(5-x)/10$
Simplifying
$y=5/10-x/10$
$y=0.5-0.1x$
Arranging in the form
$y=mx+c$
$y=-0.1x+0.5$
Slope
$m=-0.1$
Intercept
$c=0.5$

How do you find the slope and intercept of y=(5-x)/10y=(5-x)/10?