How do you solve x+y=6 and x-y=2?

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How do you solve x+y=6 and x-y=2?

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Answer 1 · 2018-03-11T10:00:14

$x = 4$ $x=4$
$y = 2$ $y=2$

Explanation:

$x + y = 6 ∣ - y$ $x+y=6|-y$
$x = 6 - y$ $x=6-y$

$x - y = 2$ $color(red)(x)-y=2$
$6 - y - y = 2$ $color(red)(6-y)-y=2$
$6 - 2 y = 2 ∣ - 6$ $6-2y=2|-6$
$- 2 y = - 4 ∣ : (- 2)$ $-2y=-4|:(-2)$
$y = 2$ $y=2$

$x + y = 6$ $x+color(blue)(y)=6$
$x + 2 = 6 ∣ - 2$ $x+color(blue)(2)=6|-2$
$x = 4$ $x=4$

Answer 2 · 2018-03-11T10:00:19

$x = 4$ $x = 4$

Explanation:

We can eliminate $y$ $y$ from the equation by adding the two together, as $y + - y = y - y = 0$ $y + -y = y-y = 0$
We must also add the other terms.
$2 x = 8$ $2x = 8$
$x = 4$ $x = 4$

Answer 3 · 2018-03-11T10:03:59

$x = 4, y = 2$ $x= 4, y= 2$

Explanation:

$x + y = 6$ $x+y=6$ , and $x - y = 2$ $x-y=2$
You can eliminate it or subtitute it.

A. Eliminate

$x + y = 6$ $x+y=6$
$x - y = 2$ $x-y=2$
______ -
$2 y = 4, y = 2$ $2y=4, y=2$
And it makes $x = 4$ $x=4$

B. Subtitute

$x + y = 6$ $x+y=6$
$y = 6 - x$ $y=6-x$

$x - y = x - (6 - x) = 2$ $x-y=x-(6-x)=2$

$2 x - 6 = 2$ $2x-6=2$
$2 x = 8, x = 4$ $2x=8, x=4$
$x + y = 4 + y = 6, y = 2$ $x+y=4+y=6, y=2$

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How do you solve x+y=6 and x-y=2?

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