How do you write an equation of a circle whose diameter has endpoints (-4, 2) and (4, -4)?

Question

3747 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-11T19:14:51

$x^2 +y^2+2y=24$

This is the equation of the circle.

The equation of a circle with given end points of Diameter as $(x_1,y_1),(x_2,y_2)$ is $(x-x_1)(x-x_2)+(y-y_1)(y-y_2)=0$

Using this formula we get the equation as :-

$(x-(-4))(x-4)+(y-2)(y-(-4))=0$

$rArr(x+4)(x-4)+(y-2)(y+4)=0$

$rArrx^2 +y^2+2y-24=0$

$:.x^2 +y^2+2y=24$