Question

How do you solve `4^x = 12`?

Answer 1

`x=1.79`

Explanation:

Apply the `log_4` on both sides of the equation

`log_4(4^x)=log_4(12)`

Apply an Exponent Logarithm Law:
`x* log_4(4)=log_4(12)`

`log_a(a)` always equals 1, so you get:
`x=log_4(12)`

If your calculator doesn't have log bases besides the default (10) you can apply the change of base formula:
`x=log(12)/log(4)`