Prove the following identities?

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Prove the following identities?

Cscx-sinx/secx=cos^3x

1 Answer

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Answer 1 · 2018-03-13T03:43:50

Couldn't prove because they aren't equal

Explanation:

$\frac{csc x - sin x}{sec x} = {cos}^{3} x$ $(Cscx-sinx)/secx=cos^3x$

$\frac{\frac{1}{sin x} - \frac{{sin}^{2} x}{sin x}}{\frac{1}{cos x}} = {cos}^{3} x$ $(1/sinx-sin^2x/sinx)/(1/cosx)=cos^3x$
$(\frac{1 - {sin}^{2} x}{sin x}) \cdot cos x = {cos}^{3} x$ $((1-sin^2x)/sinx)*cosx=cos^3x$
$(\frac{{cos}^{2} x}{sin x}) \cdot cos x = {cos}^{3} x$ $((cos^2x)/sinx)*cosx=cos^3x$
$\frac{{cos}^{3} x}{sin x} = {cos}^{3} x$ $cos^3x/sinx=cos^3x$

They are not equal...

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Prove the following identities?

Cscx-sinx/secx=cos^3x

1 Answer

Explanation:

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