How do you solve $41 = - 4 (- n + 3) - 3 (5 n + 8)$ $41= - 4( - n + 3) - 3( 5n + 8)$ ?

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Answer 1 · 2018-03-13T04:52:33

$- 7 = n$ $-7=n$

$41 = - 4 (- n + 3) - 3 (5 n + 8)$ $41=-4(-n+3) -3(5n+8)$
So start by distributing on the right side so you end up with

$41 = 4 n - 12 - 15 n - 24$ $41=4n -12 -15n-24$

Then simplify

$41 = 4 n - 15 n - 24 - 12$ $41=4n -15n-24-12$

$41 = 4 n - 15 n - 36$ $41=4n -15n-36$

$41 = - 11 n - 36$ $41=-11n-36$

$41 + 36 = - 11 n$ $41+36=-11n$

$77 = - 11 n$ $77=-11n$

$\frac{77}{- 11} = \frac{- 11 n}{- 11}$ $(77)/-11=(-11n)/-11$

$- 7 = n$ $-7=n$

How do you solve 41= - 4( - n + 3) - 3( 5n + 8)41=−4(−n+3)−3(5n+8)41= - 4( - n + 3) - 3( 5n + 8)?