If i have 4.00 moles of gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

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If i have 4.00 moles of gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

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Answer 1 · 2018-03-13T09:45:46

$67.3 K$ $67.3"K"$

Explanation:

Use the equation
$P V = n R T$ $PV=nRT$

$P = 5.6 atm = 5.6 \times 10^{5} Pa$ $P= 5.6 "atm"= 5.6 xx 10^5 "Pa"$
$V = 12 L = \frac{12}{1000} m^{3}$ $V=12 "L"=12/1000"m"^3$
$n = 4 mol$ $n=4"mol"$
$R = 8.31 J/mol$ $R=8.31 "J/mol"$ ( this is always constant)
$T$ $T$ is unknown

By rearranging the equation....

$T = \frac{P V}{n R}$ $T=(PV)/(nR)$
Thus,
$T = 67.3 K$ $T=67.3 "K"$

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If i have 4.00 moles of gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

1 Answer

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