How do you subtract $(9v + 5) - ( 9v + 5)$ ?

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Answer 1 · 2018-03-13T11:43:17

0

Both expressions are the same. If you subtract 4 from 4, the result is zero.

Or you can remove the parentheses and process the arithmetic;
$9v+5 -9v-5=9v-9v+5-5=0$

Answer 2 · 2018-03-13T11:45:47

To subtract $(9v+5)-(9v+5$ ), we can expand first and then simplify like terms.

Answer: $0$

We are given this expression ( $9v+5)-(9v+5)$ and we are trying to find an answer to this.

First, we will expand the second bracket which is $-(9v+5)$
Remember the negative in front of the bracket represents $-1$ .

Now we multiply $-1$ by all the numbers in the bracket, so we multiply $-1$ by $9v$ which is equal to $-9v$ and $-1 xx 5$ which is $-5$ .

$-(9v+5) = -9v-5$

Now that we have expanded the bracket, we have the expression:

$9v+5-9v-5$

We can put like terms together and simplify as much as we can.

$9v-9v =0, and 5-5 = 0.$

$9v+5-9v-5=0$

How do you subtract (9v + 5) - ( 9v + 5)(9v + 5) - ( 9v + 5)?