Two bodies are projected at angle theta and 90 minus theta to the horizontal with the same speed the ratio of their maximum vertical height is?

1 Answer
Mar 13, 2018

the ratio of their maximum height = (Tantheta )^2

Explanation:

As the two bodies are being projected with velocity u
at angle theta

and (90-theta) respectively ,

their velocity component in vertical direction will be

u. sin (theta) and

u .sin(90-theta) = u cos theta respectively.

At the maximum height the final velocity (v) in vertical

direction will be zero for both bodies.

Therefore
using the relation between u, v and

the distance traversed h one can write -

v^2 = u^2 - 2.g. h

in which v=0 ; We get

h = u^2/ (2g) and

for first body height will be

h1=( u.sintheta )^2 /(2g)

and for the second body

h2 = (u cos theta)) ^2/(2g)

so (h1)/ (h2 )= (Tan Theta)^2