A ball is shot from cannnon into air with upward velocity of 40 ft/sec. The equation that gives the height(h) of the ball at any time id h(t)= -16t^2+40t+1.5. How many seconds rounded to the nearest hundreth will it take the ball to reach the ground?

1 Answer
Jane
Mar 13, 2018

#2.56s#

Explanation:

Given equation is #h=-16t^2 +40t+1.5#

Put,#t=0# in the equation,you will get,#h=1.5# that means,the ball was shot from #1.5 ft# above the ground.

So,when after going upto a maximum height (let,#x#),it reaches the ground,its net displacement will be #x-(x+1.5)=-1.5ft#(as upward direction is taken positive as per the equation given)

So,if it takes time #t# then,putting #h=-1.5# in the given equation,we get,

#-1.5=-16t^2 +40t+1.5#

Solving this we get,

#t=2.56s#

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