Question

Make 30.0 mL of H2 gas from the reaction of 6M HCL and Aluminum. How do I do the Stoichiometry for this problem?

I think the chemical equation is:

3HCl + Al -----> Al(Cl)3 + H3

Answer 1

24.1 mg of aluminium

Explanation:

The chemical equation is `6 HCl + 2 Al -> 2 AlCl_3 + 3 H_2`.
30 mL of `H_2` correspond to 1.34 millimoles .According to stoichiometric ratio, 3 moles of `H_2` come from 2 moles of `Al`, therefore 1.34 mmoles come from 0.89 mmoles of Aluminium, =24.1 milligrams