Is $(2, 3)$ $(2, 3)$ a solution to $2 x + y = 8$ $2x+y=8$ ?

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Is $(2, 3)$ $(2, 3)$ a solution to $2 x + y = 8$ $2x+y=8$ ?

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Answer 1 · 2018-03-14T11:27:51

Nop

Explanation:

Plug in $(2, 3)$ $(2,3)$ into the equation $2 x + y = 8$ $2x + y = 8$

$2 (2) + (3) = 8$ $2( 2 ) + ( 3 ) = 8$

Simplify

$4 + 3 = 8$ $4 + 3 =8$
$7 \neq 8$ $7 != 8$

So the ordered pair $(2, 3)$ $(2,3)$ is not a solution to $2 x + y = 8$ $2x + y = 8$

Answer 2 · 2018-03-14T11:33:10

No, $(2, 3)$ $(2,3)$ is not a solution of $2 x + y = 8$ $2x+y=8$ .

Explanation:

To check whether $(2, 3)$ $(2,3)$ is a solution or not, we simply substitute the values in our equation $2 x + y = 8$ $2x + y = 8$
$2 \cdot 2 + 3 = 8$ $2*2+3=8$
$7 = 8$ $7=8$
which is false, so $(2, 3)$ $(2,3)$ is not a solution to $2 x + y = 8$ $2x+y=8$ .

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Is $(2, 3)$ $(2, 3)$ a solution to $2 x + y = 8$ $2x+y=8$ ?

2 Answers

Explanation:

Explanation:

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