Question

Two bodies are projected at angle theta and 90 minus theta to the horizontal with the same speed the ratio of their horizontal ranges are?

Answer 1

`1:1`

Explanation:

Formula for range of a projectile is `R=(u^2 sin 2 theta)/g` where,`u` is the velocity of projection and `theta` is the angle of projection.

For,`u` be the same for both the bodies,

`R_1 : R_2 = sin 2theta : sin 2(90-theta)=sin 2theta: sin(180-2theta)=sin 2 theta : sin 2theta=1:1` (as, `sin(180-2theta)=sin 2theta`)