Question

How do you prove 1+cos2A/cos2A=tan2A/tanA?

Answer 1

see below

Explanation:

We have,
L.H.S=`frac{1+cos2A}(cos2A`
=`frac{2cos^2A}(cos2A`
Multiplying sinA in both numerator and denominator,
=`frac{2cos^AsinA}(cos2AsinA`
If we rearrange it,then
`frac{sin2A//cos2A}(sinA//cosA`
Whis is equal to `tan2A//tanA` {R.H.S}