Question

Upon reaching a downward velocity of 100 miles per hour, 300 newions of drag resist the diver's motion. How large is the skydiver's acceleration?

Answer 1

`(10m-300)/m`

Explanation:

Let's assume the mass of the skydiver be `m`.

Therefore, the his weight would be `mg ~~10m" Newtons"`

At velocity of 100mph, force of drag `=300" Newtons"`

Net Force `= (10m-300)N`

`"Aceleration" = "Force"_"net"/"mass"`

`=>a=(10m-300)/m`