How do you solve $6( - 2- 3p ) = - 6+ 4( 1- 5p )$ ?

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Answer 1 · 2018-03-18T07:45:27

$p=5$

We have, $6(-2-3p)=-6+4(1-5p)$
Or, $-12-18p=-6+4-20p$
Or, $2p=12-2$
Or, $2p=10$
Thus, $p=5$

Answer 2 · 2018-03-18T07:45:56

If you multiply the numbers before the parenthesis in, then you will have an ordinary equation.

$p=5$

$6(-2-3p) = -6+4(1-5p)$

You'd get :

$-12 - 18p = -6 + 4 - 20p$

Which would be simplified as:

$2p = 10$

Which would mean that :

$p = 5$

How do you solve 6( - 2- 3p ) = - 6+ 4( 1- 5p )6( - 2- 3p ) = - 6+ 4( 1- 5p )?