How do you factor the expression $9 x^{2} - 16$ $9x^2 - 16$ ?

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Answer 1 · 2018-03-20T07:12:57

$(3 x + 4) (3 x - 4)$ $(3x+4)(3x-4)$

$9 x^{2} - 16$ $9x^2-16$

$\Rightarrow {(3 x)}^{2} - {(4)}^{2}$ $=> (3x)^2-(4)^2$

The identity for $a^{2} - b^{2}$ $a^2-b^2$ is equal to

$(a + b) (a - b)$ $(a+b)(a-b)$ .

Here , $a = 3 x$ $a=3x$ and $b = 4$ $b=4$ .

So , we get ${(3 x)}^{2} - {(4)}^{2}$ $(3x)^2-(4)^2$

$\Rightarrow (3 x + 4) (3 x - 4)$ $=> (3x+4)(3x-4)$

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